9.34 mole of electrons are required for electrolysis of molten NaCl.
To find the number of use this expression
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Here,
Mass of Na = 215 g
Molar mass of Na = 23 g/mol
Now put the values in above expression
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{215\ g}{23.0\ \text{g/mol}}[/tex]
= 9.34 mol
Now write the half reaction for electrolysis of molten NaCl
Na⁺ + 1e⁻ → Na(s)
From the above reaction we can say that 1 moles of electrons are transferred to deposit 1 mol of Na metal.
Na metal = [tex]9.34\ \text{mol} \times 1\ \text{mol Na} \times \frac{1\ \text{mole}\ e^-}{1\ \text{mol Na}}[/tex]
= 9.34 mole e⁻
Thus from the above conclusion we can say that 9.34 mole of electrons are required for electrolysis of molten NaCl.
Learn more about the Moles here: brainly.com/question/15356425
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