grams of radium can form by passing 235 C through an electrolytic cell containing a molten radium salt is 0.2752 g
Given
The balanced half-reaction is,
Ra⁺²(aq) + 2e⁻ → Ra (s)
Now given Coloumb of charge = 235 C
1 Mole of Ra⁺² contains charge of 2 Faraday
hence
1 Mole of Ra⁺² = 2 Faraday
= 2× 96485 C
= 192970 C
So,
192970 C= 1 Mole of Ra⁺²
1 C = [tex]\frac{1}{192970}[/tex] mole of Ra⁺²
= 5.1821 × 10⁻⁶ mole of Ra⁺²
235 C = 5.1821 × 10⁻⁶ × 235 mole of Ra⁺²
= 0.0012178 mole of Ra⁺²
Mass of Ra⁺² = 0.0012178 × 226.025 g
= 0.2752 g
Thus from the above conclusion we can say that grams of Ra that formed by passing 235C through an electrolytic cell containing a molten radium salt is 0.2752 g .
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