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A mercury mirror forms inside a test tube as a result of the thermal decomposition of mercury(II) oxide:
2HgO(s) → 2Hg(l) + O₂(g) ΔH = 181.6kJ(a) How much heat is absorbed to decompose 555 g of the oxide?

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tanisharawat014

232.66kj heat is absorbed to decompose 555g of the oxide .

Given that ,

A mercury mirror forms inside a test tube as a result of the thermal decomposition of mercury (II) oxide .

Enthalpy change of the above reaction that the heat of formation, = delHrxn =181.6kj ( endothermic reaction , because it is positive )

Heat absorbed = 275kj

We know, the molar mass of HgO = 216.6 g

mass of 2 moles of HgO = 2( 216.6) = 433.2 g

Then ,

Heat required to decompose 2 moles of HgO ( 433.2g) = 181.6kj

Heat required to decompose 555g of HgO

= 181.6kj (555G)/433.2g = 232.66kj

Hence , 232.66kj heat is absorbed to decompose 555g of the oxide .

Learn more about endothermic reaction here :

brainly.com/question/6506846

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