Two voltaic cells are to be joined so that one will run the other as an electrolytic cell. In the first cell, one half-cell has Au foil in 1.00 M Au(NO₃)₃, and the other half-cell has a Cr bar in 1.00 M Cr(NO₃)₃. In the second cell, one half-cell has a Co bar in 1.00 M Co(NO₃)₂, and the other half-cell has a Zn bar in 1.00 M Zn(NO₃)₂.(b) Calculate the total potential if the two cells are connected as voltaic cells in series.

Respuesta :

The total potential if the two cells are connected as voltaic cells in series is 2.72 volts.


What is the potential or a voltaic cell?

The potential of a voltaic cell is the measure of potential difference between the two half cells of the voltaic cell.

The reduction potential for the given elements are as follows:
1) Au³⁺ + 3e−  ⇌  Au(s)       E°= 1.50
2) Cr³⁺ + 3e−  ⇌  Cr(s)       E°= –0.74
3) Co²⁺ + 2e−  ⇌  Co(s)       E°= –0.28
4) Zn²⁺(aq) + 2e−  ⇌  Zn(s)   E°= –0.76

The first cell is made up of Gold (Au) and Chromium (Cr). Since the concentration of both the half cells is the same i.e. 1.00M and change in electrons in each half cell is also same i.e. 3 electron change, The potential of the first cell can be obtained by the formula

E°(cell) = E°(anode) - E°(cathode)
Here the anode is Chromium half cell and cathode is Gold half cell.

Hence,

E°(cell 1) = 1.50 - (–0.74)
              = 1.50 + 0.74
E°(cell 1) = 2.24 volts  

Similarly in the second cell, anode is Zinc half cell and cathode is Cobalt half cell.
Hence,

E°(cell 2) = –0.28 - (–0.76)
              = 0.76 - 0.28
E°(cell 2) = 0.48 volts

As both these cells are connected to each other in series, the total potential of the two voltaic cells together is the sum of their individual cell potentials.

E°(series) = E°(cell 1) + E°(cell 2)

               = 2.24 + 0.48
E°(series) = 2.72 volts

Thus, the total potential if the two cells are connected as voltaic cells in series is 2.72 volts.

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