The total potential if the two cells are connected as voltaic cells in series is 2.72 volts.
The potential of a voltaic cell is the measure of potential difference between the two half cells of the voltaic cell.
The reduction potential for the given elements are as follows:
1) Au³⁺ + 3e− ⇌ Au(s) E°= 1.50
2) Cr³⁺ + 3e− ⇌ Cr(s) E°= –0.74
3) Co²⁺ + 2e− ⇌ Co(s) E°= –0.28
4) Zn²⁺(aq) + 2e− ⇌ Zn(s) E°= –0.76
The first cell is made up of Gold (Au) and Chromium (Cr). Since the concentration of both the half cells is the same i.e. 1.00M and change in electrons in each half cell is also same i.e. 3 electron change, The potential of the first cell can be obtained by the formula
E°(cell) = E°(anode) - E°(cathode)
Here the anode is Chromium half cell and cathode is Gold half cell.
Hence,
E°(cell 1) = 1.50 - (–0.74)
= 1.50 + 0.74
E°(cell 1) = 2.24 volts
Similarly in the second cell, anode is Zinc half cell and cathode is Cobalt half cell.
Hence,
E°(cell 2) = –0.28 - (–0.76)
= 0.76 - 0.28
E°(cell 2) = 0.48 volts
As both these cells are connected to each other in series, the total potential of the two voltaic cells together is the sum of their individual cell potentials.
E°(series) = E°(cell 1) + E°(cell 2)
= 2.24 + 0.48
E°(series) = 2.72 volts
Thus, the total potential if the two cells are connected as voltaic cells in series is 2.72 volts.
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