Respuesta :
Balanced formation equation at standard conditions Na (s) + [tex]\frac{1}{2}[/tex]H₂ (g) + C (s, graphite) + [tex]\frac{3}{2}[/tex] O₂ (g) → NaHCO₃ (s) [ΔH° (Na (s)) = 0, ΔH° (H₂ (g)) = 0 and ΔH° (C (s, graphite)) = 0 and ΔH° (O₂ (g)) = 0].
What is Chemical Reaction ?
A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form a other new substances.
The chemical reaction for NaHCO₃ is
Na (s) + H₂ (g) + C (s, graphite) + O₂ (g) → NaHCO₃ (s)
Reactant Side Product Side
Na = 1 Na = 1
H = 2 H = 1
C = 1 N = 1
O= 2 O = 3
In the reactant side there are 2 H atoms and in the product side 1H atoms. So multiply by [tex]\frac{1}{2}[/tex] in the reactant side to balance H atoms.
Na (s) + [tex]\frac{1}{2}[/tex]H₂ (g) + C (s, graphite) + O₂ (g) → NaHCO₃ (s)
Reactant Side Product Side
Na = 1 Na = 1
H = 1 H = 1
C = 1 N = 1
O= 2 O = 3
In the reactant side there are 2 O atoms and in the product side 3 O atoms. So multiply by [tex]\frac{3}{2}[/tex] in the reactant side to balance O atoms.
Na (s) + [tex]\frac{1}{2}[/tex]H₂ (g) + C (s, graphite) + [tex]\frac{3}{2}[/tex] O₂ (g) → NaHCO₃ (s)
Reactant Side Product Side
Na = 1 Na = 1
H = 1 H = 1
C = 1 N = 1
O = 3 O = 3
Now the above equation is balanced.
Now, write the balanced formation equation at standard conditions
Na (s) + [tex]\frac{1}{2}[/tex]H₂ (g) + C (s, graphite) + [tex]\frac{3}{2}[/tex] O₂ (g) → NaHCO₃ (s) [ΔH° (Na (s)) = 0, ΔH° (H₂ (g)) = 0 and ΔH° (C (s, graphite)) = 0 and ΔH° (O₂ (g)) = 0]
Thus from the above conclusion we can say that Balanced formation equation at standard conditions Na (s) + [tex]\frac{1}{2}[/tex]H₂ (g) + C (s, graphite) + [tex]\frac{3}{2}[/tex] O₂ (g) → NaHCO₃ (s) [ΔH° (Na (s)) = 0, ΔH° (H₂ (g)) = 0 and ΔH° (C (s, graphite)) = 0 and ΔH° (O₂ (g)) = 0]
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