The energy released in the redox reaction
2PbSO₄(s) + 2H₂O(l) → Pb(s) + PbO₂(s) + 2H₂SO₄ is -1032kJ/mol.
In the electrolytic or dead cell, at anode electron entering the cell.
It is a device that is used for the conversion of the electrical energy of non-spontaneous redox reactions to a chemical energy.
In the electrolytic cell, at anode which is negative electrode of Electrolytic cell oxidation occurs and at cathode which is positive electrode of Electrolytic cell, reduction occurs.
The reaction in which both reduction and oxidation reaction take place simultaneously is known as redox reaction.
The reaction in which a substance or compound or species looses its electron. In this reaction, oxidation state of an element increases.
The reaction in which a substance or compound or species accept thr electron. In this reaction, oxidation state of an element decreases.
Reaction at cathode:
SO₃(g) + H₂O(l) → H₂SO₄(l) ΔH°rxn -132kJ
At anode:
Pb(s) + PbO₂(s) +2SO₃(g) → 2PbSO₄(s) ΔH°rxn = -768kJ
By reversing equation (2) , multiplying (1) by 2 and adding both the reaction, we get
redox reaction:
2PbSO₄(s) + 2H₂O(l) → Pb(s) + PbO₂(s) + 2H₂SO₄
∆H = ΔH°(cathode) - ΔH°(anode)
ΔH° = -264 - 768
= -1032kJ/mol
Thus, we concluded that the energy released in the redox reaction
2PbSO₄(s) + 2H₂O(l) → Pb(s) + PbO₂(s) + 2H₂SO₄ is -1032kJ/mol.
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