Respuesta :
N2O+2CO2+3H2O 2CH2O+2NO3+2H+NH+4+O2NO3 (Nitrification) (half reaction) NH+4N5+O23O2 (half reaction) NH+4+O2NO3 is the overall balanced equation that was obtained (Nitrification)
N undergoes oxidation as its oxidation state increases from 3 to +5, and O undergoes reduction as its oxidation state decreases from 0 to -2 during the reaction. The process's oxidation and reduction components will be as follows: NH+4→N5+O2→3O2− The following equations are produced by adding protons to balance H atoms and water molecules to balance O atoms:
In order to balance charges, we add electrons using NH+4NH5++4H+2O2+2H+3O2+H2OWe. Next, the equations state: CH2O + H2OCO2 + 4H++4e (III) 2NO−3+10H++8e−→N2O+5H2O —-(IV) The following equation, which will make gained electrons equal to lost electrons, is obtained by multiplying equation (III) by two: — 2CH2O + 2H2O + 2CO + 8H++ (V) After adding equations (IV) and (V), the complete balanced chemical equation is as follows:
N2O+2CO2+3H2O 2CH2O+2NO3+2H+
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