Respuesta :
Oxidation number of Cu in Cu₂S , Cu₂O and Cu is 2,2 and 0 respectively.
Oxidation number is the charge felt by an atom in a species when all other atoms bonded to it are removed. It can be positive, negative, zero or fractional. Increase in oxidation number is considered as oxidation while its decrease is termed as reduction. Species that aids in reduction of other species and itself undergoes oxidation is termed as reducing agent while the one that aids in oxidation of other species and itself undergoes reduction is termed as oxidizing agent.
The reaction involved is
Cu₂S(s)+2Cu₂O(s)→6Cu (l)+ SO2 (g)
The species involved are Cu₂S, Cu₂O and Cu. In Cu, the oxidation number of Cu is zero.
It is so, because Cu is in elemental form.
In Cu₂S, oxidation number of S is -2.
Calculate the oxidation number of Cu (assumed as x) as shown below:
2x-2=0
x = +1
Similarly, oxidation number of O is -2,
calculate the oxidation number of Cu is Cu₂O as shown below
2x-2=0
x = +1
Hence, oxidation number of Cu in Cu₂S Cu₂O and Cu is 2,2 and 0 respectively.
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