Final temperature if the average specific heat capacity of the products is 2.5 J/g·°C is 1302.57°C
Given reaction:
C₂H₄O(g) → CH₄(g) + CO(g)
Now,
Given data for this reaction is :
ΔH°f =-77.4 kJ/mol
ΔH°vaporization =569.4 J/g
= 569.4J/g × 44.0g/mol
ΔH°vaporization= 25.082 kJ/mol
Now,
ΔH°vaporization = H(vapor) - H(liquid)
25.082 = H(vapor) + 77.4 kJ/mol
H(vapor) = -52.318 kJ/mol
Again,
ΔH°rxn = ( H( CO(g))) + (H(CH₄(g))) - (H( C₂H₄O(g)))
= -110.5 - 74.87 + 52.318
ΔH°rxn = -133.053 kJ/mol
Now,
Given
T₁= 93°C = 366K
We know that,
Q= mcΔT
133.053 × 10³ = 44 × 2.5 × (T₂ - 93)
T₂ = 1302.57°C
Thus, from the above conclusion we can say that , Final temperature if the average specific heat capacity of the products is 2.5 J/g·°C is 1302.57°C .
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