The obtained balanced equation is 2C12H26+37O2→24CO2+26H2O
C12H26+18/12O2→12CO2+13H2O
Take the C atoms first. 12 must form 12 CO2 on the right because there are 12 on the left.
The H atoms are then balanced. Since there are 26 on the left, 13 H2O must be formed there.
The O atoms should always come last.
There are 12 x 2 (24), 13 x 1 (37), and so on.
Therefore, the left side needs 37 O atoms. Since oxygen is delivered as O2 molecules, we require 37/2 = 1812 O2 molecules to supply these 37 O atoms.
You cannot have 18.5 molecules, hence 18.12 does not relate to them.
18.5 moles of oxygen molecules are mentioned.
All the species might easily be multiplied by two to yield:
2C12H26+37O2→24CO2+26H2O
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