Respuesta :
48.5 × 10² km could the car travel on the 20.4 gal of fuel.
What is Chemical Reaction ?
A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form a other new substances.
Now write the chemical equation for isooctane
[tex]C_{8}H_{18} (l) + \frac{25}{2} O_{2} (g) \rightarrow 8CO_{2} (g) + 9H_{2} O (g) ,\,\,\, \Delta H_{\txt{rxn}}^{\circ} = -5.44 \times 10^{3}\ \text{kJ/mol}[/tex]
Isooctane volume (V) = 20.4 gal
Isooctane density (d) = 0.692 g/mL
Now, find the energy released during the reaction
[tex]E = 20.4\ \text{gal}\ C_{8}H_{18} \times \frac{3.78\ L}{1\ \text{gal}} \times \frac{1000\ mL}{1.0\ L} \times \frac{0.692\ g}{1\ mL} \times \frac{1\ \text{mol}\ C_{8}H_{18}}{114.0\ g\ C_8H_{18}} \times \frac{-5.44 \times 10^3\ kJ}{1\ \text{mol}\ C_8H_{18}}[/tex]
= -2.55 × 10⁶ kJ
Now if the whole energy is transfer to wheel, then
[tex]= 2.55 \times 10^{6}\ kJ \times \frac{1\ h}{5.5 \times 10^4\ kJ} \tims \frac{65\ \text{miles}}{1\ h} \times \frac{1.6093\ km}{1\ \text{mile}}[/tex]
= 48.5 × 10² km
Thus from the above conclusion we can say that 48.5 × 10² km could the car travel on the 20.4 gal of fuel.
Learn more about the Chemical Reaction here: https://brainly.com/question/11231920
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