The corresponding parts are:
- <A = <A' = <A"
- <B = <B' = <B"
- <C = <C' = <C"
- AB = A'B' = A"B"
- AC = A'C' = A"C"
- BC = B'C' = B"C"
How to compare the sides
The statement is given as:
△ABC was transformed using two rigid transformations.
The rigid transformations imply that:
The images of the triangle after the transformation would be equal
So, the corresponding parts are:
- <A = <A' = <A"
- <B = <B' = <B"
- <C = <C' = <C"
- AB = A'B' = A"B"
- AC = A'C' = A"C"
- BC = B'C' = B"C"
Why the results are true?
The results are true because rigid transformations do not change the side lengths and the angle measures of a shape
How to prove that two triangles are congruent without using rigid transformations?
To do this, we simply make use any of the following congruent theorems:
- SSS: Side Side Side
- SAS: Side Angle Side
- AAS: Angle Angle Side
How to respond to this classmate?
The classmate's claim is that
Only two pairs of corresponding parts are enough to prove the congruent triangle
The above is true because of the following congruent theorems:
- SSS: Side Side Side
- SAS: Side Angle Side
Read more about congruent theorems at
https://brainly.com/question/2102943
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