Respuesta :

The energy difference for the transition in hydrogen atoms for 1 mol is  1.82285 * 10^2 KJ / mol

1 / λ = Rh(1 / n1^2 - 1 / n2^2)

ΔE = Rh (1 / n1^2 - 1 / n2^2)

Rh = 2.18 * 10^-18

ΔE = 2.18 * 10^-18 * (1 / 2^2 - 1 / 3^2)

ΔE = 2.18 * 10^-18 *(1 / 4 - 1 / 9)

ΔE = 3.027 * 10^-19 J

(ΔE)1mol =  ΔE * [tex]N_{A}[/tex]

(ΔE)1mol = 3.027 * 10^-19 * 6.022 * 10^23

(ΔE)1mol = 182285.94 J/mol

(ΔE)1mol = 182.285 KJ / mol

(ΔE)1mol = 1.82285 * 10^2 KJ / mol

The energy difference for the transition in hydrogen atoms for 1 mol is  1.82285 * 10^2 KJ / mol

For more information click on the link below:

https://brainly.com/question/11176460

# SPJ4

Complete question:

Calculate the energy difference for the electron transition of n = 3 to n = 2 for 1.00 mol of hydrogen atoms.