Respuesta :
Mole fraction exists a unit of concentration. In the solution, the relative amount of solute and solvents exists measured by the mole fraction and it exists represented by “X.”
Molarity = 4.54 M
Molality = 5.11 m
mol fraction NH₃ = 4.54 mol / 53.87 mol = 0.084
mol fraction [tex]$H_2O[/tex] = 49.33 mol / 53.87 mol = 0.916
mol fraction contains no units.
How to find the molality, molarity, and mole fraction of NH₃?
Take 1.0 L of this solution
Mass = 965.1 g
Mass of NH₃ = 8/100 [tex]*[/tex] 965.1g = 77.21 g
Molar mass NH₃ = 17 g/mol
mol NH₃ in 77.21 g = 77.21g / 17g/mol
= 4.54 mol in 1.0 L solution
Molarity = 4.54 M
You contain 4.54 mol NH₃ dissolved in 965.1g - 77.21 g
= 887.89 g of water
mol NH₃ dissolved in 1.0 kg water = 4.54 mol [tex]*[/tex] 1000 ml/kg / 887.89 g
= 5.11 mol
Molality = 5.11 m
Mol [tex]$H_2O[/tex] in 887.89 g = 887.89 g/18 g/mol = 49.33 mol [tex]$H_2O[/tex]
Mol NH₃ = 4.54
Total moles = 49.33 + 4.54 = 53.87 mol
mol fraction NH₃ = 4.54 mol / 53.87 mol = 0.084
mol fraction [tex]$H_2O[/tex] = 49.33 mol / 53.87 mol = 0.916
mol fraction contains no units.
To learn more about mol fraction refer to:
https://brainly.com/question/14783710
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