The wavelength of radiation that could cause the photoelectric effect in calcium is [tex]&\lambda=4.32[/tex]×[tex]10^{-7} m[/tex]
The photoelectric effect is a phenomenon that results in electrically charged particles being discharged from or within a substance when it absorbs electromagnetic radiation. When light strikes a metal plate, the action is frequently described as the ejection of electrons from the plate.
For calcium, the wavelength will be
[tex]$\begin{aligned}&\mathrm{E}=4.6^{*} 10^{-19} \mathrm{~J} \\&\mathrm{~h}=6.626^{*} 10^{-34} \mathrm{Js} \\&\mathrm{c}=3^{*} 10^{8} \mathrm{~m} / \mathrm{s} \\&\mathrm{E}=\frac{h c}{\lambda} \\&\lambda=\frac{h c}{E} \\&\lambda=\frac{6.626 * 10^{-34} \mathrm{Js} * 3 * 10^{8} \mathrm{~m} / \mathrm{s}}{4.6 * 10^{-19} \mathrm{~J}} \\&\lambda=4.32^{*} 10^{-7} \mathrm{~m}\end{aligned}$[/tex]
The wavelength of radiation that could cause the photoelectric effect in calcium is [tex]&\lambda=4.32[/tex] ×[tex]10^{-7} \mathrm{~m}[/tex].
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