Respuesta :
the fraction that will be remaining after 10.0 x 10^4 yrs is :
144 x [tex]e^{-0.000121 * 10 * 10^{4} }[/tex]
WHAT IS CARBON - 14 ?
Mono-carbon, commonly known as 0-methane and atomic carbon, is a colorless gaseous inorganic compound having the chemical formula C. (also written [C]). At room temperature and pressure, it is kinetically unstable and is eliminated through auto-polymerization.
The simplest form of carbon is atomic carbon, which is also the source of carbon clusters. The monomer of all (condensed) carbon allotropes, including graphite and diamond, may also be examined.
CALCULATION
the half life of carbon - 14 is [tex]t_{1/2}[/tex] = 5730 yrs
this means that 5730 yrs , the initial amount of carbon -14 will be halved
the radioactive constant is
λ = ln 2 / [tex]t_{1/2}[/tex]
= ln 2 / 5730
= 0.000121
the fundamental decay question is
m = [tex]m_{0}[/tex] [tex]e^{-λt}[/tex]
the initial amount of carbon - 14 is [tex]m_{0}[/tex] = 144 g
the time is t = 10 x 10^4 yrs
m = 144 x [tex]e^{-0.000121 * 10 * 10^{4} }[/tex]
learn more about carbon-14 here :
brainly.com/question/4206267
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