The mass of NH₄ClO₄ needed to react for every kilogram of Al is 4.351 Kg
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
3Al + 3NH₄ClO₄ -> Al₂O₃ + AlCl₃ + 3NO + 6H₂O
Molar mass of Al = 27 g/mol
Mass of Al from the balanced equation = 3 × 27 = 81 g = 81 / 1000 = 0.081 Kg
Molar mass of NH₄ClO₄ = 117.5 g/mol
Mass of NH₄ClO₄ from the balanced equation = 3 × 117.5 = 352.5 g = 352.5 / 1000 = 0.3525 Kg
SUMMARY
From the balanced equation above,
0.081 Kg of Al reacted with 0.3525 Kg of NH₄ClO₄
From the balanced equation above,
0.081 Kg of Al reacted with 0.3525 Kg of NH₄ClO₄
Therefore,
1 Kg of Al will react with = (1 × 0.3525) / 0.081 = 4.351 Kg of NH₄ClO₄
Thus, 4.351 Kg of NH₄ClO₄ is needed for the reaction.
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