The original number will be 35.
Let the digit at ones place be x
And digit at tens place be y
Then the original number would be written as = 10y + x
And its reversed number would be written as = 10x + y
As when the numbers are reversed the digit at ones place is replaced with the ten’s place. Hence digit at tens place will be x and at ones place will be y.
According to the question we have been given that ,
Sum of two digit number is 8, that is ,
x + y = 8 (1)
If numbers are reversed, new number = 18 + original number
That is, 10x + y =18 + (10y + x) (2)
Therefore equation (1) and (2) are the required linear equation. By solving this we will get the required digits,
10x+y = 18 + 10y + x
9x = 18 + 9y
Putting the value of x from equation (1) in equation (3)
9(8-y) = 18 + 9y
72 – 9y = 18 +9y
18y = 54
y = 3
therefore, x = 5
Thus the original number will be = 10(3) + 5 = 35
Learn more about linear equation here : https://brainly.com/question/26310043
#SPJ9