The sum of the digits of a two-digit numeral is 8. If the digits are reversed, the new number is 18 greater than the
original number. Find the original numeral.

Respuesta :

The original number will be 35.

Let the digit at ones place be x

 And digit at tens place be y

Then the original number would be written as = 10y + x

And its reversed number would be written as = 10x + y

As when the numbers are reversed the digit at ones place is replaced with the ten’s place. Hence digit at tens place will be x and at ones place will be y.

According to the question we have been given that ,

     Sum of two digit number is 8, that is ,

                                          x + y = 8           (1)

    If numbers are reversed, new number = 18 + original number

      That is,         10x + y =18 + (10y + x)           (2)

Therefore equation (1) and (2) are the required linear equation. By solving this we will get the required digits,

                         10x+y = 18 + 10y + x

                          9x = 18 + 9y

Putting the value of x from equation (1) in equation (3)

            9(8-y) = 18 + 9y

            72 – 9y = 18 +9y

              18y = 54

                 y = 3

      therefore, x = 5

Thus the original number will be = 10(3) + 5 = 35

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