log10 x +log10 y= 4, log10 x + 2 log 10 y =3 simultaneous logarithm equation

The solution to the system of equation is (10^5, 10^-1)
Simultaneous equations are two or more algebraic equations that share variables.
Given the system of equations below
log10 x +log10 y= 4,
log10 x + 2 log 10 y =3
Subtract to have;
log10 y - log10 y^2 = 4 - 3
log10(y/y^2) =1
y/y^2 = 10^1
1/y = 10
y = 1/10
Substitute y = 1/10 into any of the equation to have;
log 10 x + log10 (1/10) = 4
log10 x - 1 = 4
log10 x = 5
x = 10^5
Hence the solution to the system of equation is (10^5, 10^-1)
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