Respuesta :

[tex]\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh ~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ h=14\\ A=161 \end{cases}\implies 161=\cfrac{1}{2}b(14) \\\\\\ 161=7b\implies \cfrac{161}{7}=b\implies 23=b[/tex]

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