Respuesta :
The distance from Chenoa's house to the coffee shop is M = 6 units.
The distance from Chenoa's house to her school is P = 7.5 units.
The distance from Chenoa's coffee to the school is R = 1.5 units.
Given,
Chenoa wants to stop for coffee on her way to school.
The distance from Chenoaʼs house to the coffee shop is 3 miles more than twice the distance from the coffee shop to Chenoaʼs school.
The total distance from Chenoaʼs house to her school is 5 times the distance from the coffee shop to her school.
Let the distance from Chenoa's house to the coffee shop is M.
Let the distance from Chenoa's house to her school is P.
Let the distance from Chenoa's coffee shop to the school is R.
<-----------------------p----------------------------------->
House___________Coffee shop________________School
<-----M------------> <---------R----------------->
We have,
M = 2R + 3______(a)
P = 5R______(b)
We see that,
P = M + R______(c)
Find R
From (b) and (c)
M + R = 5R
M = 4R
Putting in (a)
4R = 2R + 3
2R = 3
R = 3/2 = 1.5
Putting in (b)
P = 5 x 3/2 = 15/2
P = 15/2 = 7.5
M = 4 x 3/2 = 12/2
M = 12/2 = 6
Thus,
The distance from Chenoa's house to the coffee shop is M = 6 units.
The distance from Chenoa's house to her school is P = 7.5 units.
The distance from Chenoa's coffee to the school is R = 1.5 units.
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