Challenge You are given the numbers, (31+ n.3. Vn+ 16). Find the smallest value of n so that all of the numbers in the set are natural numbers.
The smallest value of n that makes all of the numbers in set natural numbers is

Respuesta :

The smallest value of 'n' that makes all the number in set natural numbers is 1.

What are Natural Numbers?

Positive Whole numbers are comes under the Natural Numbers.

Whole Numbers → { 0, 1, 2, 3, 4, -------∞ }

Natural Numbers → { 1, 2, 3, 4, 5, -------∞ }

Note: '0' is not a natural number.

Smallest Natural number is '1'.

In the given set ( 31 + n, 3, √n+ 16 ).

These numbers will be natural numbers if value of n is perfect square and the minimum perfect square value is '1'.

We are taking 'n' as perfect square because if we put non-perfect square value so value of √n will not be always a Natural Number.

For example: if n = 2 then √2 = 1.414

if n = 3 then √3 = 1.73

here, Put n = 1 so,

31 + n = 31 + 1 = 32

3 = 3            

√n + 16 = √1 + 16 = 17         ( √1 = 1 )

now, given set will become ( 32, 3, 17 ).

Hence, The smallest value of 'n' that makes all the number in set natural numbers is 1.

Learn more about "Natural Number and Set of Numbers" from here: https://brainly.com/question/4829377

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