A sample of zirconium is made by reacting 58.30 g of zirconium
tetrachloride, ZrCl4, with excess magnesium.
ZrCl4 + 2Mg → Zr + 2MgCl₂
The mass of zirconium produced is 20.52 g. Calculate the percentage
yield of zirconium. (Ar values: Zr = 91.2, Cl = 35.5, Mg = 24.3)

Respuesta :

The percentage yield of zirconium is 90%.

What is Balanced Chemical Equation ?

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The given balanced chemical equation

ZrCl₄ + 2Mg → Zr + 2MgCl₂

How to find the number of moles ?

Number of moles =  [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

                             = [tex]\frac{58.3}{233.2}[/tex]

                             = [tex]\frac{1}{4}[/tex] mole

Theoretical yield mass of Zr = [tex]\frac{1}{4} \times 91.2[/tex]

                                               = 22.8 g

How to find the Percentage yield ?

To find the percentage yield use this formula

% yield = [tex]\frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100\%[/tex]

            = [tex]\frac{20.52}{22.80} \times 100\%[/tex]

            = 90 %

Thus from the above conclusion we can say that the percentage

yield of zirconium is 90%.

Learn more about the Balanced chemical equation here: brainly.com/question/26694427

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