The percentage yield of zirconium is 90%.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The given balanced chemical equation
ZrCl₄ + 2Mg → Zr + 2MgCl₂
Number of moles = [tex]\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{58.3}{233.2}[/tex]
= [tex]\frac{1}{4}[/tex] mole
Theoretical yield mass of Zr = [tex]\frac{1}{4} \times 91.2[/tex]
= 22.8 g
To find the percentage yield use this formula
% yield = [tex]\frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100\%[/tex]
= [tex]\frac{20.52}{22.80} \times 100\%[/tex]
= 90 %
Thus from the above conclusion we can say that the percentage
yield of zirconium is 90%.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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