Respuesta :
A linear (y = mx + b), quadratic (y = ax²), or exponential (y = a(b)*) function that models the data is 1000(810/1000)^x.
The slope-intercept version of the equation for a straight line is written as Y = mx + b.
The parabola-like form of the y=ax^2 graph. The graph would be situated depending on the sign of a.
x y
-10 1000
-9 810
-8 640
-7 490
-6 360
Now, y=mx+b
Forming the equation, and subtracting
1000=m(-10)+b ______(1)
810=m(-9)+b _______(2)
-___________________
190=-m
m=-190
now, substituting the value of m in equation 1
Thus, b=-900
y=-190x-900
If y=ax^2
at x=-10
y=1000
1000=a(-10)(-10)
1000=100a
10=a
Thus y=10x^2
=>y=ab^x
substituting x=-10, y=1000
1000=ab^(-10)
(1000)b^-10=a
and
810=ab^-9
(810)(b^-9)=a
Thus b = 810/1000 and a=1000
So, y=1000(b)^x=1000(810/1000)^x
To learn more about linear, quadratic and exponential problems from the given link:
https://brainly.com/question/11515427
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