The factorization of the expression y³ - 23y² + 142y - 120 is (y - 1) (y - 12) (y - 10).
y³ - 23y² + 142y - 120
= y³ - y² - 22y² + 22y + 120y - 120
= y²(y - 1) - 22y(y - 1) + 120(y - 1)
= (y - 1) (y² - 22y + 120)
= (y - 1) (y² - 12y - 10y + 120)
= (y - 1) y(y - 12) - 10(y - 12)
= (y - 1) (y - 12) (y - 10)
Therefore, the factorization of the expression y³ - 23y² + 142y - 120 is (y - 1) (y - 12) (y - 10).
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