A large right triangle is going to be a part of a geometric sculpture, as shown below. The hypotenuse will be 2525​ feet long. The length of one leg of the triangle is 1010​​ feet​ more​ than twice the other leg. Find the length of each leg, in feet, and separate them with a comma.

Respuesta :

The lengths of the legs of the right triangle are 7 and 24. That is,

7, 24

Calculating the length of the leg of a right triangle

From the question, we are to calculate the length of each leg of the right triangle

From the given information,

Hypotenuse of the right triangle = 25 feet

The length of one leg of the triangle is 10 feet​ more​ than twice the other leg

Let the length of the other leg be x

Then,

Length of one of the legs = 10 + 2x

Using the Pythagorean theorem, we can write that

(10 + 2x)² + x² = 25²

(10 + 2x)(10 + 2x) + x² = 625

100 + 20x + 20x + 4x² + x² = 625

100 + 40x + 5x² = 625

5x² + 40x = 625 - 100

5x² + 40x = 525

Divide through by 5

x² + 8x = 105

x² + 8x - 105 = 0

Solve quadratically

x² +15x -7x - 105 = 0

x(x + 15) -7(x + 15) = 0

(x -7)(x + 15) = 0

x - 7 = 0 OR x + 15 = 0

x = 7 OR x = -15

Since x cannot be negative, the value of x is 7

Recall,

The length of one of the legs = 10 + 2x

= 10 + 2(7)

= 10 + 14

= 24

Hence, the lengths of the legs of the right triangle are 7 and 24. That is, 7, 24

Learn more on Calculating the legs of a right triangle here: https://brainly.com/question/917409

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