Respuesta :
The final concentration of [Ca2+] is 0.125 M.
The balanced chemical reaction for the reaction of calcium chloride and sulfuric acid is shown below.
[tex]CaCl_2 + H_{2}SO_{4}[/tex] → [tex]CaSO_4 + 2HCl[/tex]
[tex]CaCl_2 + 2H^{+} + SO_{4}^{2-}[/tex] → [tex]Ca^{2+} +SO_{4}^{2-} + 2HCl[/tex]
[tex]CaCl_2 + 2H^{+}[/tex]→[tex]Ca^{2+} + 2HCl[/tex]
First, let us solve for the number of moles of CaCl2 and H2SO4.
mol CaCl2 = (molarity CaCl2)*(volume CaCl2)
mol CaCl2 = (0.50 M)(100 mL)( 1 L/1000 mL)
mol CaCl2 = 0.05 mol
mol H2SO4 = (molarity H2SO4)*(volume H2SO4)
mol H2SO4 = (0.25 M)(100 mL)( 1 L/1000 mL)
mol H2SO4 = 0.025 mol
Then, solve for the mol of H+ using the molar ratio of H+ and H2SO4
mol H+ = 0.025 mol H2SO4 * ( 2 mol H+ / 1 mol H2SO4)
mol H+ = 0.05 mol H+
Determine the final concentration of Ca2+ based on its stoichiometric ratio with H+
mol Ca2+ = 0.05 mol H+ * (1 mol Ca2+ / 2 mol H+)
mol Ca2+ = 0.025 mol Ca2+
molarity Ca2+ = 0.025 mol Ca2+ / [(100 mL + 100 mL)* ( 1 L/1000 mL)]
molarity Ca2+= 0.125 M
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