Respuesta :
Taking into account the definition of photon and energy of a photon, the energy of a mole of photons with a frequency of 3.10 kHz is 2.0553×10⁻³⁰ J.
Photon and energy of a photon
You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".
The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.
The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:
E=h×f
Energy of the photon in this case
In this case, you know:
- h= 6.63*10⁻³⁴ Js
- f= 3.10 kHz= 3100 Hz (being 1 kHz= 1000 Hz)
Replacing:
E= 3100 Hz× 6.63×10⁻³⁴ Js
Solving:
E= 2.0553×10⁻³⁰ J
Finally, the energy of a mole of photons with a frequency of 3.10 kHz is 2.0553×10⁻³⁰ J.
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