5! permutation of the letters abcdefgh contains strings ab, de, and gh.
The number of permutations of 'n' objects taken 'r' at a time is determined by the following formula:
P(n,r)=n! / (n−r)!
We can also find permutation using the Selection and Formation Method:
For example:
1. Number of ways to arrange the letter SANOJ:
here number of alphabets are 5, and we have to arrange all the letter so using permutation formula:
P(5, 5 ) = 5! / (5-5)!
P(5, 5 ) = 5! : 0! = 1
without using the formula we can simply write 5! as the answer.
Here, we have given the word, " abcdefgh "
and we have to make those arrangements in which ab, de, and gh come together:
so now, we will count ab, de, and gh as a single word.
now, we will have 5 different words/alphabet:
1 → ab
2 → c
3 → de
4 → f
5 → gh
Number of ways to arrange all the 5 words/alphabet: 5!
Hence,
5! permutation of the letters abcdefgh contains strings ab, de, and gh.
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