Respuesta :
An equation in slope-intercept form of the line that is a segment bisector of both AB (1,6) (7,8)and CD (3,8) (7,12) is; y = 3x - 5
How to write an equation in slope intercept form?
The equation of a line in slope intercept form is; y = mx + c
wher;
m is the slope and c is the intercept
The midpoint or bisector (x, y) of a line with endpoints at (x1, y1) and (x2, y2) is;
x = (x1 + x2)/2 and y = (y1 + y2)/2
Thus;
Midpoint of AB is;
(1 + 7)/2, (6 + 8)/2 = (4, 7)
Midpoint of CD is;
(3 + 7)/2, (8 + 12)/2 = (5, 10)
Midpoint of BC is;
(7 + 3)/2, (8 + 8)/2 = (5, 8)
Midpoint of ADis;
(1 + 7)/2, (6 + 12)/2 = (4, 9)
The equation of the line passing through the midpoints of AB and CD is given as:
(y - 7)/(x - 4) = (10 - 7)/(5 - 4)
y - 7 = 3(x - 4)
y = 7 + 3x - 12
y = 3x - 5
Read more about Slope Intercept Form at; https://brainly.com/question/17339253
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