Subtracting the answers from the expansion gives 8x² - 12x - S
How to determine the difference
Given the expressions;
(3x-1)², (x+6)²
First, expand the bracket;
( 3x - 1) ( 3x + 1) ⇒ difference of two squares
9x² + 3x - 3x - 1²
9x² - 1 (1)
( x + 6) (x + 6)
x² + 6x + 6x + 36
x² + 12x + 36 (2)
Now, let's substract (2) from (1)
9x² - 1 - (x² + 12x + 36 ) expand bracket
9x² - 1 -x² - 12x - 36
collect like terms
9x² - x² - 12x - 36 - 1
8x² - 12x - 37
Thus, subtracting the answers from the expansion gives 8x² - 12x - 37
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