Since David throws a fastball in a baseball game. the distance that the baseball go in 1 second is 135.
What is the distance about?
Note that the ball moves 27/2 feet in 1/10 second.
Therefore:
Based on the above conditions, we shall formulate the equation as: [tex]\frac{27}{2} / \frac{1}{10}[/tex]
Then we need to Divide a fraction using the multiplication of its reciprocal and thus it will be: [tex]\frac{27}{2} x 10[/tex]
Then we need to remove the common factor: 27 x 5
Then lastly we Calculate the product/quotient: 135
Therefore, Since David throws a fastball in a baseball game. the distance that the baseball go in 1 second is 135.
Learn more about distance from
https://brainly.com/question/2854969
#SPJ1
