Respuesta :
By using Hubble's constant H₀, the estimated age of the universe would be 27,269,816,110 years.
As we know that the age of the universe is something near to the time the galaxies needed to reach their current distance:
T = D/V
where T is the time the galaxies needed, D is distance and V is speed.
By using Hubble's law we can use the equation
V = H₀*D
where H₀ is Hubble's constant
By combining these 2 equations, we get
T = D/(H₀*D) = 1/H₀ .............(A)
In conclusion, the age of the universe is something near the inverse of Hubble's constant.
From the question above, we know that:
H₀ = 11 km/s/Mly
By using equation A we get
T = 1/(11 km/s*Mly)
T = (1/11) s*Mly/km
Convert 1 million light-years to km by (1 ly = 9.461*10^12 km)
T = (1/11) s*Mly/km
T = (1/11)*9.461*10^18 s
T = 8.6009*10^17 s
Convert to years by (1 year = 3.154*10^7 s)
T = 8.6009*10^17 s
T = (8.6009*10^17 s/3.154*10^7 s)* 1 yea
T = 27,269,816,110 years.
Learn more about Hubble's constant at: https://brainly.com/question/27051032
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