Respuesta :
Answer:
18
Step-by-step explanation:
Distance Formula: [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Plug the points into the formula and solve
[tex]=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\=\sqrt{(28-28)^2+(6+12)^2}\\=\sqrt{(0)^2+(18)^2}\\=\sqrt{324}\\=18[/tex]
The distance between the two given points (28,-12) and (28,6) is 18.
What is the distance between the two given points?
Formula for the distance between two points is expressed as;
D = √( ( x₂ - x₁)² + ( y₂ - y₁ )²
Given the data in the question;
For point (28,-12)
- x₁ = 28
- y₁ = -12
For point (28,6)
- x₂ = 28
- y₂ = 6
We plug in the values into the formula above.
D = √( ( 28 - 28)² + ( 6 - (-12) )²
D = √( ( 0 )² + ( 6 + 12 )²
D = √( 0 + ( 18 )² )
D = √( 0 + 324 )
D = √( 324 )
D = 18
Therefore, the distance between the two given points (28,-12) and (28,6) is 18.
Learn more about distance formula here: https://brainly.com/question/28280765
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