A viscous oil enters a 50 mm diameter pipe section. The oil has a density of 986 kg/m3 and a viscosity of 0.01 kg/m.s and flows at a rate of 0.01 m3/min. The entrance length is 1.2526m.
Given, D (diameter of pipe) = 50mm = 0.05m
e (density) = 986 kg/[tex]m^{3}[/tex]
μ ( viscosity) = 0.01kg/m.s
flowrate = 0.01[tex]m^{3}[/tex]/min
= 0.000166[tex]m^{3}[/tex]/sec
Solution:
velocity = (flow rate)/ cross sectional area
= 0.000166/{(π/4)*([tex]D^{2}[/tex])
= 0.000166/{(π/4)*([tex]0.05^{2}[/tex])
= 0.000166/0.00196 = 0.08469 m/sec
Re = DVe/μ
= (0.05)*(0.8469)*(986)/0.01
= 417.5408
Re < 2100 so flow is laminas
Le/D = 0.06 Re
Le = 0.06*(417.5408)*(0.05)
Le = 1.2526m
The entrance length is 1.2526m
Density is the number of things—which could be people, animals, vegetation, or objects—in a certain area. To calculate density, you divide the wide variety of items by the measurement of the area. The population density of a country is the number of people in that country divided by the area in square kilometers or miles.
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