How long must a constant current of 50.0 a be passed through an electrolytic cell containing aqueous cu2 ions to produce 5.50 moles of copper metal?

Respuesta :

The answer is 5.36 Hr.

According to Faraday's law,

W=(ECt) / 96500

Where W mass of metal deposited = number of moles x molar mass

=5.00 mol x 63.54 (g/mol)

=317.7 g

E= Equivalent weight of Cu =63.54/2=31.77C

current= 50 A

time taken ,t = ?

Plug the values we get,

t= 96500 W/EC

19300s x ( 1 min/60s) x(1 hr/60min)

t=5.36 hr

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