The probability that the three numbers are a solution to the equation x + y + z = 27 will be 0.1664.
It should be noted that the numbers are from 0 to 27. Therefore, there are 28 numbers.
The number of ways to selecting 3 out or 28 will be:
= 28 × 28 × 28
Therefore, the probability will be:
= 29C26/(28 × 28 × 28)
= 0.1664
Therefore, the probability is 0.1664.
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