The rate law for the reaction at some temperature is if the half-life for this reaction is 2.00 s when [nobr]0 = 1.0 m, calculate the value of k for this reaction.

Respuesta :

The value of the k = 0.50 l/mol-1

2NOBr(g) 2NO(g) + Br2(g)

at some temperatures is

Rate = - Δ[NOBr]/Δt = k[NOBr]^2

The value of the k = 0.50 l/mol-1

A rate law shows how the rate of a chemical reaction depends on reactant concentration. For a reaction such as aA → products, the rate law generally has the form rate = k[A]ⁿ, where k is a proportionality constant called the rate constant and n is the order of the reaction concerning A.

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