Respuesta :

The solution to the system of linear equations is x = -9, y =5 and x = 0

How to determine the solution to the system of linear equations?

The system of linear equations is given as:

x + 2y + 3z = 1

2x + 4y + 7z = 2

3x + 7y + 11z = 8

Multiply the equation x + 2y + 3z = 1 by 2.

So, we have:

2x + 4y + 6z = 2

Subtract 2x + 4y + 6z = 2 from 2x + 4y + 7z = 2

So, we have:

2x - 2x + 4y - 4y + 7z - 6z = 2 - 2

Evaluate the like terms

z = 0

Substitute z = 0 in the equations.

So, we have:

2x + 4y = 2

3x + 7y = 8

Multiply 2x + 4y = 2 by 3 and 3x + 7y = 8 by 2

So, we have:

6x + 12y = 6

6x + 14y = 16

Subtract the equations

-2y = -10

Divide by -2

y = 5

Substitute y = 5 in 3x + 7y = 8

3x + 7 * 5 = 8

This gives

3x = 8 - 35

So, we have

3x = -27

Divide by 3

x = -9

Hence, the solution to the system of linear equations is x = -9, y =5 and x = 0

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