The number of neutrons possessed by an isotope beryllium-9 is 5.
Neutron is a subatomic particle forming part of the nucleus of an atom and having no charge.
The number of neutrons in the atom of an element can be calculated by subtracting the number of protons or atomic number from the mass number.
That is; no. of neutrons = mass number - no of protons
According to this question, Beryllium has an atomic number or proton number of 4. The number of neutrons in an isotope of beryllium-9 is as follows:
no of neutrons = 9 - 4 = 5
Therefore, the number of neutrons possessed by an isotope beryllium-9 is 5.
Learn more about neutrons at: https://brainly.com/question/13131235
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