The acceleration of the rocket is 5.5m/s².
To find the acceleration of the rocket:
Given:
Kinematic Equation:
Use the kinematic equation as follows:
[tex]$\begin{aligned}&Y=V_o+V_o t+\frac{1}{2} a t^2 \\&y=0+0+\frac{1}{2} a(4)^2 \\&y=8 a\end{aligned}$[/tex]
The bolt took 6 seconds to hit the ground.
[tex]$\begin{aligned}&Y=V_o+V_o t-\frac{1}{2} g t \\&0=8 a+4 a(6)-\frac{1}{2} * 9.8 * 6^2 \\&32 a=176.4 \\&a=5.5 m / s^2\end{aligned}$[/tex]
Therefore, the acceleration of the rocket is 5.5m/s².
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The complete question is given below:
A rocket is launched straight up with constant acceleration. Four seconds after liftoff, a bolt falls off the side of the rocket. The bolt hits the ground 6.0 s later. What was the rocket’s acceleration?