If a proton is fired toward the plates with the same speed v0, will it be deflected up, deflected down, or pass through with no deflection?

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25-08-2022
Physics

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If a proton is fired toward the plates with the same speed v0, will it be deflected up, deflected down, or pass through with no deflection?

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Tutorconsortium217 Tutorconsortium217 · Answer 1 · 2022-09-04T20:19:40+02:00

The influence of the electric field balances the effect of the magnetic field on the electron in this situation. The magnetic field's magnitude on the electron is given by FB = (-e) (v x B), and as a result, the electron is forced upward.

However, the amount of electric force is also identical. Fe = (-e) From the negative plate (up) to the positive plate (down), E exerts a force on the electron that balances the magnetic force acting on it. As a result, the electron passes between the plates without being deflected. hence, FB = Fe

The magnetic field in the case of the proton exerts a magnetic force with a magnitude of FB = e (v x B) downward or towards the positive plate, but the positively charged proton opposes the positive plate, which means the electric force acting on the proton is from the positive plate to the negative plate. As a result, the two forces cancel one another out, and the proton passes through the plates with no deflection.

The electron and proton don't encounter any deflection in either scenario.

How does the magnetic field affect the proton and electron?

The magnetic field is a vector (directional) field that can be either uniform or non-uniform.
The magnetic field affects the electron and proton by exerting a force on them.

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