Respuesta :
The equation between KOH and H₃PO₄ is shown below:
3KOH+H₃PO₄⇒K₃PO₄+3H₂O
The balanced equation shows that one mole of H₃PO₄ requires three moles of KOH.
Therefore further calculation is done as follows:
1mol H₃PO₄= 3mol KOH
0.0023625 mol H₃PO₄= 0.0023625×3mol KOH
= 0.0070875 mol KOH
Substitute 0.200 M as the given molarity of KOH and 0.0070875 mol as the number of moles in Equation 1.
Molarity = (Number of moles of solute/Volume of solutions in litres)
0.200 M= (0.0070875 mol/Volume of KOH in litres)
Volume of KOH in litres = (0.0070875 mol/ 0.200M)
= 0.0354 L
The volume of KOH added to the solutions is 0.0354 L.
How is the equivalency point determined?
The equivalency point for acid-base titrations can be identified quite quickly.
A simple pH meter is used to measure the pH of the solution being titrated after different amounts of titrant have been introduced to create a titration curve. The curve can then be read to determine the equivalency point.
To know more about Equivalency Point visit:
https://brainly.com/question/14782315
#SPJ4
