Respuesta :
If the Oxygen is replaced by helium at the same temperature, then [tex]\frac{0.7625}{P1}[/tex] × m1 Kg of latter needed to produce a gauge pressure of 6.10 atm.
Where m1 is mass of the Oxygen used and P1 is the pressure produced by Oxygen.
What is Gauge Pressure?
The pressure as compared to atmospheric pressure is known as gauge pressure. For pressures above atmospheric pressure, gauge pressure is positive; for pressures below it, it is negative.
Absolute pressure is a measurement of pressure that uses zero or no reference pressure at all. The only natural environment where zero pressure can exist is in a perfect vacuum, which can only be found in space. As a result, the atmospheric (ambient) pressure plus gauge pressure equals an absolute-pressure reading.
Calculation of mass of Helium gas.
Let,
m1 = Mass of Oxygen gas , P1 = Pressure of Oxygen
m2 = Mass of Helium gas , P2 = Pressure of Helium
V1 = V2 = V = Volume of tank
M1 = Molecular mass of Oxygen , M2 = Molecular mass of helium gas
n = number of moles of atoms.
Now, according to gas equation. When Oxygen was not replaced,
P1 × V1 = n1 × R × T
P1 × V = [tex]\frac{m1}{M}[/tex] × R × T
P1 × V = [tex]\frac{m1}{32}[/tex] × R × T ....(1)
When Oxygen was replaced by helium,
P2 × V2 = n2 × R × T
6.10 × V = [tex]\frac{m2}{M2}[/tex] × R ×T
6.10 × V = [tex]\frac{m2}{4}[/tex] × R × T ....(2)
Divide equation (2) by (1), we get
[tex]\frac{6.10}{P1}[/tex] = [tex]\frac{m2}{m1}[/tex] × [tex]\frac{32}{4}[/tex]
m2 = 0.7625 × [tex]\frac{m1}{P1}[/tex] Kg
To know more about the gauge pressure visit: https://brainly.com/question/14570197
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