Based on the fact that the cards are replaced, the probability of picking an ace exactly two times is 0.47%
As the cards are replaced, this makes this an independent probabilities problem.
The probability of getting an ace exactly two times is:
= Probability of getting ace once x Probability of getting ace once x Probability of not getting ace³
Solving gives:
= 4/52 x 4/52 x (48/52)³
= 0.47%
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