What is the value of x? *
YR is a perpendicular bisector of
HB. HY = 7x+13, HW = 8y-15,
WB = 3y + 21, and YB = 12x - 12.
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Respuesta :

The value of x if YR is a perpendicular bisector of HB is 5

How to determine the value of x?

The given parameters are:

YR is a perpendicular bisector of HB.

HY = 7x + 13

HW = 8y - 15

WB = 3y + 21

YB = 12x - 12.

The statement "YR is a perpendicular bisector of HB" implies that:

The line segment YR divides the line segment HB into equal halves

So, we have the following equation

HY = YB

Substitute the known values in the above equation

7x + 13 = 12x - 12

Collect the like terms in the above equation

7x - 12x = -13 - 12

Evaluate the like terms in the above equation

-5x = -25

Divide both sides of the equation by -5

x = 5

Hence, the value of x if YR is a perpendicular bisector of HB is 5

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https://brainly.com/question/11006922

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