Company A charges 3.50 per month plus 0.15 $ per text. Company B charges 6.00$ plus 0.10 per text . How many texts would make the two plans cost the same amount?

An equation is the equality existing between two algebraic expressions connected through the equals sign in which one or more unknown values, called unknowns, appear in addition to certain known data.

The solution of a equation means determining the value that satisfies it. In this way, by changing the unknown to the solution, the equality must be true.

To solve an equation, keep in mind:

When a value that is adding, when passing to the other member of the equation, it will subtract.
If a value you are subtracting goes to the other side of the equation by adding.
When a value you are dividing goes to another side of the equation, it will multiply whatever is on the other side.
If a value is multiplying it passes to the other side of the equation, it will pass by dividing everything on the other side.

Amount of texts

Being "t" the amount of text, you know that:

Company A charges 3.50 per month plus 0.15 $ per text → Cost for company A= 3.50 + 0.15t
Company B charges 6.00$ plus 0.10 per text → Cost for company B= 6.00 + 0.10t

If the two plans cost the same amount, the equation is:

Cost for company A= Cost for company B

3.50 + 0.15t= 6.00 + 0.10t

Solving:

0.15t - 0.10t = 6.00 - 3.50

0.05t= 2.50

t= 2.50 ÷ 0.05

t= 50

Finally, 50 texts would make the two plans cost the same amount.

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