The equation of parabola is [tex]y=1/4x^{2}+x/2-4\\\\[/tex].
A symmetrical open plane curve formed by the intersection of a cone with a plane parallel to its side. The path of a projectile under the influence of gravity follows a curve of this shape. A plane curve generated by a point moving so that its distance from a fixed point is equal to its distance from a fixed line.
Given:
The equation of parabola in vertex form is
[tex]y=a(x-h)^{2} +k[/tex]
Being vertex here
h=-2
k=-5
According to given question we have
∴
Equation of parabola in vertex form is
[tex]y=a(x+2)^{2} -5[/tex]
. The parabola passes through point (4,4) So the point (4,4) will satisfy the equation .
[tex]4=a(4+2)^{2} -5\\\\4=a*36-5\\\\9=a*36\\\\a=9/36\\\\a=1/4[/tex]
Hence the equation of parabola is
[tex]y=1/4(x+2)^{2} -5\\\\y=1/4(x^{2} +4+2x)-5\\\\y=1/4x^{2} +1+x/2-5\\\\y=1/4x^{2}+x/2-4\\\\[/tex]
Therefore, the equation of parabola is [tex]y=1/4x^{2}+x/2-4\\\\[/tex].
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the equation of parabola is missing