A child traveling 5 m/s on a sled passes her younger brother. If her average acceleration on the sledding hill is 2 m/s^2. how fast is she passes her older brother 4 s later?

Respuesta :

Answer:

13 m/s

Explanation:

Given average acceleration a and initial velocity  v0 we can compute the final velocity  using the equation

a = (v - v0)/t where t is the time taken to reach final velocity from initial velocity

Here a = 2 m/s² and v0 is the initial velocity when she passes her younger brother v0 = 5m/s.

It takes t = 4 s to pass her older brother at which time her speed is v, say

Then

a = (v - v0)/t

Plugging in known values,

2 = (v - 5)/4

Switch sides:
(v- 5)/4 = 2

Multiply both sides by 4:
v - 5  = 8

v =5 + 8 = 13 m/s - the speed at which she passes her older brother