Considering the sum of the internal angles of the polygon, it is found that the measures of the angles A and B are given as follows;
What is the sum of the internal angles of a polygon?
The sum of the internal angles of a polygon with n vertices is given by the following equation:
S = (n - 2) x 180º.
For this problem, the polygon has 6 vertices, hence n = 6 and the sum is given by:
S = (6 - 2) x 180º = 720º.
Considering each internal angle, we can solve for x as follows:
13x + 2 + 16x + 7 + 88 + 155 + 170 + 95 = 720
29x + 517 = 720
29x = 203
x = 203/29
x = 7.
Then the measures are given as follows:
- Angle A: 16 x 7 + 7 = 119º.
- Angle B: 13 x 7 + 2 = 93º.
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